(x^2-9)/(2x-12)=0

Solution for (x^2-9)/(2x-12)=0 equation:

(x^2-9)/(2x-12)=0


Domain of the equation: (2x-12)!=0

We move all terms containing x to the left, all other terms to the right

2x!=12

x!=12/2

x!=6

x∈R


We multiply all the terms by the denominator


(x^2-9)=0

We get rid of parentheses

x^2-9=0

a = 1; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·1·(-9)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*1}=\frac{6}{2}
=3
$